Quiz (1 point)
Given that:
instruction #21 is
load dst=3 addr=1 imm=0
the PC at time 21 = 21
value of cell 1 at time 21 = 123
value of cell 123 at time 21 = 5
Prove that:
value of cell 3 at time 22 = 5
The following properties may be helpful:
- a + 0 = a
- 21 + 1 = 22
if the following are true:
- instruction #i is
load dst=dst addr=addr imm=imm
- the PC at time t = i
then value of cell dst at time (t + 1) = value of cell ((value of cell addr at time t) + imm) at time t
- instruction #i is
if a = b, then a + c = b + c
if the following are true:
- a = b
- b = c
then a = c
if (value of cell 1 at time 21) + 0 = 123, then value of cell ((value of cell 1 at time 21) + 0) at time 21 = value of cell 123 at time 21
if the following are true:
- a = b
- b = c
then a = c
if the following are true:
- a = b
- b = c
then a = c
if 21 + 1 = 22, then value of cell 3 at time (21 + 1) = value of cell 3 at time 22
if the following are true:
- a = b
- a = c
then b = c
Please write your proof in the table below. Each row should contain one claim. The last claim is the statement that you are trying to prove.