The following example shows that when a LOAD instruction with dst = 5 is executed, memory cell #2 stays unchanged.

Quiz (1 point)

• not (2 = 5)
• 0 + a = a

• if the following are true:

  • instruction #i is load dst=dst addr=addr imm=imm
  • the PC at time t = i
  • not (other = dst)

  then value of cell other at time (t + 1) = value of cell other at time t

• if 0 + 1 = 1, then value of cell 2 at time (0 + 1) = value of cell 2 at time 1

• if the following are true:

  • a = b
  • a = c

  then b = c

Please write your proof in the table below. Each row should contain one claim. The last claim is the statement that you are trying to prove.

Step	Claim	Reason (optional)	Error Message (if any)
1
2
3
4
5
6
7
8
9
10

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