Proof: LOAD Instruction Example 4
Let's prove the following theorem:
if the following are true:
- instruction #0 is
load dst=5 addr=1 imm=1 - the PC at time 0 = 0
then the PC at time 1 = 1
The following example shows that when a LOAD instruction is executed, the PC is incremented by 1.
Instructions
| Memory Cells |
|---|
| Program Counter | Time |
|---|---|
| 0 | 0 |
LW Computer Simulator
Proof:
Given
| 1 | instruction #0 is load dst=5 addr=1 imm=1 |
|---|---|
| 2 | the PC at time 0 = 0 |
| # | Claim | Reason |
|---|---|---|
| 1 | the PC at time (0 + 1) = 0 + 1 | if instruction #0 is load dst=5 addr=1 imm=1 and the PC at time 0 = 0, then the PC at time (0 + 1) = 0 + 1 |
| 2 | 0 + 1 = 1 | 0 + 1 = 1 |
| 3 | the PC at time (0 + 1) = the PC at time 1 | if 0 + 1 = 1, then the PC at time (0 + 1) = the PC at time 1 |
| 4 | the PC at time 1 = 0 + 1 | if the PC at time (0 + 1) = the PC at time 1 and the PC at time (0 + 1) = 0 + 1, then the PC at time 1 = 0 + 1 |
| 5 | the PC at time 1 = 1 | if the PC at time 1 = 0 + 1 and 0 + 1 = 1, then the PC at time 1 = 1 |
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