The following example shows that when a STORE instruction with src = 5, addr = 1, and imm = 1 is executed, memory cell #4 is updated to a new value (9), but other cells, such as cell #2, remain unchanged.

Quiz (1 point)

• 3 + 1 = 4
• not (2 = 4)
• 0 + a = a

• if value of cell 1 at time 0 = 3, then (value of cell 1 at time 0) + 1 = 3 + 1

• if the following are true:

  • a = b
  • b = c

  then a = c

• if (value of cell 1 at time 0) + 1 = 4, then 2 = (value of cell 1 at time 0) + 1 = 2 = 4

• if 2 = (value of cell 1 at time 0) + 1 = 2 = 4, then not (2 = (value of cell 1 at time 0) + 1) = not (2 = 4)

• if the following are true:

  • a
  • b = a

  then b

• if the following are true:

  • instruction #i is store src=src addr=addr imm=imm
  • the PC at time t = i
  • not (other = (value of cell addr at time t) + imm)

  then value of cell other at time (t + 1) = value of cell other at time t

• if 0 + 1 = 1, then value of cell 2 at time (0 + 1) = value of cell 2 at time 1

• if the following are true:

  • a = b
  • a = c

  then b = c

Please write your proof in the table below. Each row should contain one claim. The last claim is the statement that you are trying to prove.

Step	Claim	Reason (optional)	Error Message (if any)
1
2
3
4
5
6
7
8
9
10

Add Step Reset

Become a subscriber to save your progress, see the correct answer, and more!