Quiz (1 point)
Given that:
instruction #1 is
load dst=8 addr=6 imm=1
the PC at time 1 = 1
value of cell 6 at time 1 = 3
value of cell 4 at time 1 = 11
Prove that:
value of cell 8 at time 2 = 11
The following properties may be helpful:
- 3 + 1 = 4
- 1 + 1 = 2
if the following are true:
- instruction #i is
load dst=dst addr=addr imm=imm
- the PC at time t = i
then value of cell dst at time (t + 1) = value of cell ((value of cell addr at time t) + imm) at time t
- instruction #i is
if a = b, then a + c = b + c
if the following are true:
- a = b
- b = c
then a = c
if (value of cell 6 at time 1) + 1 = 4, then value of cell ((value of cell 6 at time 1) + 1) at time 1 = value of cell 4 at time 1
if the following are true:
- a = b
- b = c
then a = c
if the following are true:
- a = b
- b = c
then a = c
if 1 + 1 = 2, then value of cell 8 at time (1 + 1) = value of cell 8 at time 2
if the following are true:
- a = b
- a = c
then b = c
Please write your proof in the table below. Each row should contain one claim. The last claim is the statement that you are trying to prove.