Quiz (1 point)
Given that:
instruction #0 is
load dst=7 addr=5 imm=0
the PC at time 14 = 0
value of cell 5 at time 14 = 10
value of cell 10 at time 14 = 45
Prove that:
value of cell 7 at time 15 = 45
The following properties may be helpful:
- a + 0 = a
- 14 + 1 = 15
if the following are true:
- instruction #i is
load dst=dst addr=addr imm=imm
- the PC at time t = i
then value of cell dst at time (t + 1) = value of cell ((value of cell addr at time t) + imm) at time t
- instruction #i is
if a = b, then a + c = b + c
if the following are true:
- a = b
- b = c
then a = c
if (value of cell 5 at time 14) + 0 = 10, then value of cell ((value of cell 5 at time 14) + 0) at time 14 = value of cell 10 at time 14
if the following are true:
- a = b
- b = c
then a = c
if the following are true:
- a = b
- b = c
then a = c
if 14 + 1 = 15, then value of cell 7 at time (14 + 1) = value of cell 7 at time 15
if the following are true:
- a = b
- a = c
then b = c
Please write your proof in the table below. Each row should contain one claim. The last claim is the statement that you are trying to prove.