Proof: Do Reverse 22 0

Let's prove the following theorem:

reverse of [ "Mexico", [ "MX", [ ] ] ] = [ "MX", [ "Mexico", [ ] ] ]

Proof:

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Proof Table
# Claim Reason
1 reverse of [ "Mexico", [ "MX", [ ] ] ] = reverse of remaining stack [ "Mexico", [ "MX", [ ] ] ] and already reversed stack [ ] reverse of [ "Mexico", [ "MX", [ ] ] ] = reverse of remaining stack [ "Mexico", [ "MX", [ ] ] ] and already reversed stack [ ]
2 reverse of remaining stack [ "Mexico", [ "MX", [ ] ] ] and already reversed stack [ ] = reverse of remaining stack [ "MX", [ ] ] and already reversed stack [ "Mexico", [ ] ] reverse of remaining stack [ "Mexico", [ "MX", [ ] ] ] and already reversed stack [ ] = reverse of remaining stack [ "MX", [ ] ] and already reversed stack [ "Mexico", [ ] ]
3 reverse of remaining stack [ "MX", [ ] ] and already reversed stack [ "Mexico", [ ] ] = [ "MX", [ "Mexico", [ ] ] ] reverse of remaining stack [ "MX", [ ] ] and already reversed stack [ "Mexico", [ ] ] = [ "MX", [ "Mexico", [ ] ] ]
4 reverse of [ "Mexico", [ "MX", [ ] ] ] = reverse of remaining stack [ "MX", [ ] ] and already reversed stack [ "Mexico", [ ] ] if reverse of [ "Mexico", [ "MX", [ ] ] ] = reverse of remaining stack [ "Mexico", [ "MX", [ ] ] ] and already reversed stack [ ] and reverse of remaining stack [ "Mexico", [ "MX", [ ] ] ] and already reversed stack [ ] = reverse of remaining stack [ "MX", [ ] ] and already reversed stack [ "Mexico", [ ] ], then reverse of [ "Mexico", [ "MX", [ ] ] ] = reverse of remaining stack [ "MX", [ ] ] and already reversed stack [ "Mexico", [ ] ]
5 reverse of [ "Mexico", [ "MX", [ ] ] ] = [ "MX", [ "Mexico", [ ] ] ] if reverse of [ "Mexico", [ "MX", [ ] ] ] = reverse of remaining stack [ "MX", [ ] ] and already reversed stack [ "Mexico", [ ] ] and reverse of remaining stack [ "MX", [ ] ] and already reversed stack [ "Mexico", [ ] ] = [ "MX", [ "Mexico", [ ] ] ], then reverse of [ "Mexico", [ "MX", [ ] ] ] = [ "MX", [ "Mexico", [ ] ] ]

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