Proof: Do Append 9

Let's prove the following theorem:

result of appending [4, 7] to [ ] = [ [4, 7], [ ] ]

Proof:

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Proof Table
# Claim Reason
1 result of appending [4, 7] to [ ] = reverse of [ [4, 7], reverse of [ ] ] result of appending [4, 7] to [ ] = reverse of [ [4, 7], reverse of [ ] ]
2 reverse of [ ] = [ ] reverse of [ ] = [ ]
3 [ [4, 7], reverse of [ ] ] = [ [4, 7], [ ] ] if reverse of [ ] = [ ], then [ [4, 7], reverse of [ ] ] = [ [4, 7], [ ] ]
4 reverse of [ [4, 7], reverse of [ ] ] = reverse of [ [4, 7], [ ] ] if [ [4, 7], reverse of [ ] ] = [ [4, 7], [ ] ], then reverse of [ [4, 7], reverse of [ ] ] = reverse of [ [4, 7], [ ] ]
5 reverse of [ [4, 7], [ ] ] = [ [4, 7], [ ] ] reverse of [ [4, 7], [ ] ] = [ [4, 7], [ ] ]
6 reverse of [ [4, 7], reverse of [ ] ] = [ [4, 7], [ ] ] if reverse of [ [4, 7], reverse of [ ] ] = reverse of [ [4, 7], [ ] ] and reverse of [ [4, 7], [ ] ] = [ [4, 7], [ ] ], then reverse of [ [4, 7], reverse of [ ] ] = [ [4, 7], [ ] ]
7 result of appending [4, 7] to [ ] = [ [4, 7], [ ] ] if result of appending [4, 7] to [ ] = reverse of [ [4, 7], reverse of [ ] ] and reverse of [ [4, 7], reverse of [ ] ] = [ [4, 7], [ ] ], then result of appending [4, 7] to [ ] = [ [4, 7], [ ] ]

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