Proof: Angle Addition Theorem 2
Let's prove the following theorem:
if point X lies in interior of ∠ABC, then (m∠ABX) + (m∠XBC) = m∠ABC
Proof:
Given
| 1 | point X lies in interior of ∠ABC |
|---|
| # | Claim | Reason |
|---|---|---|
| 1 | m∠ABC = (m∠ABX) + (m∠XBC) | if point X lies in interior of ∠ABC, then m∠ABC = (m∠ABX) + (m∠XBC) |
| 2 | (m∠ABX) + (m∠XBC) = m∠ABC | if m∠ABC = (m∠ABX) + (m∠XBC), then (m∠ABX) + (m∠XBC) = m∠ABC |
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