Proof: Congruent Triangles to Angles 2

Let's prove the following theorem:

if △ABC ≅ △DEF, then m∠EFD = m∠ACB

A B C D E F

Proof:

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Given
1 ABC ≅ △DEF
Proof Table
# Claim Reason
1 m∠BCA = m∠EFD if △ABC ≅ △DEF, then m∠BCA = m∠EFD
2 m∠EFD = m∠BCA if m∠BCA = m∠EFD, then m∠EFD = m∠BCA
3 m∠BCA = m∠ACB m∠BCA = m∠ACB
4 m∠EFD = m∠ACB if m∠EFD = m∠BCA and m∠BCA = m∠ACB, then m∠EFD = m∠ACB

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