Proof: Congruent Triangles to Distance 2
Let's prove the following theorem:
if △ABC ≅ △DEF, then distance CB = distance FE
Proof:
Given
1 | △ABC ≅ △DEF |
---|
# | Claim | Reason |
---|---|---|
1 | distance BC = distance EF | if △ABC ≅ △DEF, then distance BC = distance EF |
2 | distance CB = distance FE | if distance BC = distance EF, then distance CB = distance FE |
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