Proof: Cosine 2

Let's prove the following theorem:

if ∠ABC is a right angle, then cosine of (m∠CAB) = (distance BA) / (distance CA)

Proof:

View as a tree | View dependent proofs | Try proving it

Given
1 ABC is a right angle
Proof Table
# Claim Reason
1 cosine of (m∠BAC) = (distance BA) / (distance CA) if ∠ABC is a right angle, then cosine of (m∠BAC) = (distance BA) / (distance CA)
2 m∠BAC = m∠CAB m∠BAC = m∠CAB
3 cosine of (m∠BAC) = cosine of (m∠CAB) if m∠BAC = m∠CAB, then cosine of (m∠BAC) = cosine of (m∠CAB)
4 cosine of (m∠CAB) = (distance BA) / (distance CA) if cosine of (m∠BAC) = cosine of (m∠CAB) and cosine of (m∠BAC) = (distance BA) / (distance CA), then cosine of (m∠CAB) = (distance BA) / (distance CA)

Comments

Please log in to add comments