Proof: Midpoint Then 180
Let's prove the following theorem:
if M is the midpoint of line AB, then (m∠AMX) + (m∠XMB) = 180
Proof:
Given
1 | M is the midpoint of line AB |
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# | Claim | Reason |
---|---|---|
1 | m∠AMB = 180 | if M is the midpoint of line AB, then m∠AMB = 180 |
2 | m∠AMB = (m∠AMX) + (m∠XMB) | if m∠AMB = 180, then m∠AMB = (m∠AMX) + (m∠XMB) |
3 | (m∠AMX) + (m∠XMB) = 180 | if m∠AMB = (m∠AMX) + (m∠XMB) and m∠AMB = 180, then (m∠AMX) + (m∠XMB) = 180 |
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