Proof: Rearrange Angles

Let's prove the following theorem:

if m∠ACF = (m∠ACG) + (m∠GCF), then m∠FCA = (m∠FCG) + (m∠GCA)

A C F G

Proof:

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Given
1 m∠ACF = (m∠ACG) + (m∠GCF)
Proof Table
# Claim Reason
1 m∠FCA = (m∠ACG) + (m∠GCF) if m∠ACF = (m∠ACG) + (m∠GCF), then m∠FCA = (m∠ACG) + (m∠GCF)
2 m∠FCA = (m∠GCF) + (m∠ACG) if m∠FCA = (m∠ACG) + (m∠GCF), then m∠FCA = (m∠GCF) + (m∠ACG)
3 m∠GCF = m∠FCG m∠GCF = m∠FCG
4 m∠FCA = (m∠FCG) + (m∠ACG) if m∠FCA = (m∠GCF) + (m∠ACG) and m∠GCF = m∠FCG, then m∠FCA = (m∠FCG) + (m∠ACG)
5 m∠ACG = m∠GCA m∠ACG = m∠GCA
6 m∠FCA = (m∠FCG) + (m∠GCA) if m∠FCA = (m∠FCG) + (m∠ACG) and m∠ACG = m∠GCA, then m∠FCA = (m∠FCG) + (m∠GCA)

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