A B C D

Quiz (1 point)

Given that:
(((m∠ABC) + (m∠BCA)) + (m∠CAB)) + (((m∠ACD) + (m∠CDA)) + (m∠DAC)) = (((((m∠ABC) + (m∠BCA)) + (m∠CAB)) + (m∠ACD)) + (m∠CDA)) + (m∠DAC)

Prove that:
(((m∠ABC) + (m∠BCA)) + (m∠CAB)) + (((m∠ACD) + (m∠CDA)) + (m∠DAC)) = (((m∠ABC) + (m∠CDA)) + ((m∠BCA) + (m∠ACD))) + ((m∠DAC) + (m∠CAB))

The following properties may be helpful:

Please write your proof in the table below. Each row should contain one claim. The last claim is the statement that you are trying to prove.

Step Claim Reason (optional) Error Message (if any)
1
2
3
4
5
6
7
8
9
10

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