Proof: Similar Distances

Let's prove the following theorem:

if △ABC ∼ △DEF, then (distance AB) / (distance DE) = (distance AC) / (distance DF)

A B C D E F

Proof:

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Given
1 △ABC ∼ △DEF
Proof Table
# Claim Reason
1 (distance AC) / (distance DF) = (distance AB) / (distance DE) if △ABC ∼ △DEF, then (distance AC) / (distance DF) = (distance AB) / (distance DE)
2 (distance AB) / (distance DE) = (distance AC) / (distance DF) if (distance AC) / (distance DF) = (distance AB) / (distance DE), then (distance AB) / (distance DE) = (distance AC) / (distance DF)

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