Proof: Sine

Let's prove the following theorem:

if ∠ABC is a right angle, then sine of (m∠BAC) = (distance CB) / (distance CA)

Proof:

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Given
1 ∠ABC is a right angle
Proof Table
# Claim Reason
1 ∠CBA is a right angle if ∠ABC is a right angle, then ∠CBA is a right angle
2 sine of (m∠BAC) = (distance CB) / (distance CA) if ∠CBA is a right angle, then sine of (m∠BAC) = (distance CB) / (distance CA)

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