Proof: Sine 4

Let's prove the following theorem:

Proof:

Proof Table

#	Claim	Reason
1	sine of (m∠BCA) = (distance AB) / (distance AC)	if ∠ABC is a right angle, then sine of (m∠BCA) = (distance AB) / (distance AC) (Definition of Sine)
2	m∠BCA = m∠ACB	m∠BCA = m∠ACB (Angle Symmetry Property)
3	sine of (m∠BCA) = sine of (m∠ACB)	if m∠BCA = m∠ACB, then sine of (m∠BCA) = sine of (m∠ACB) (Substitution)
4	sine of (m∠ACB) = (distance AB) / (distance AC)	if sine of (m∠BCA) = sine of (m∠ACB) and sine of (m∠BCA) = (distance AB) / (distance AC), then sine of (m∠ACB) = (distance AB) / (distance AC) (Transitive Property of Equality Variation 2)

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