Proof: Supplementary Angles Theorem
Let's prove the following theorem:
if ∠ABX and ∠XBC are supplementary, then m∠ABC = 180
Proof:
Given
| 1 | ∠ABX and ∠XBC are supplementary |
|---|
| # | Claim | Reason |
|---|---|---|
| 1 | (m∠ABX) + (m∠XBC) = 180 | if ∠ABX and ∠XBC are supplementary, then (m∠ABX) + (m∠XBC) = 180 |
| 2 | m∠ABC = (m∠ABX) + (m∠XBC) | if (m∠ABX) + (m∠XBC) = 180, then m∠ABC = (m∠ABX) + (m∠XBC) |
| 3 | m∠ABC = 180 | if m∠ABC = (m∠ABX) + (m∠XBC) and (m∠ABX) + (m∠XBC) = 180, then m∠ABC = 180 |
Comments
Please log in to add comments