Proof: Angle Angle Side Triangle 2
Let's prove the following theorem:
if m∠ABC = m∠XYZ and m∠CAB = m∠ZXY and distance AC = distance XZ, then △BAC ≅ △YXZ
Proof:
Proof Table
# | Claim | Reason |
---|---|---|
1 | m∠CBA = m∠ZYX | if m∠ABC = m∠XYZ, then m∠CBA = m∠ZYX |
2 | m∠BAC = m∠YXZ | if m∠CAB = m∠ZXY, then m∠BAC = m∠YXZ |
3 | △BAC ≅ △YXZ | if m∠CBA = m∠ZYX and m∠BAC = m∠YXZ and distance AC = distance XZ, then △BAC ≅ △YXZ |
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