Quiz (1 point)
Given that:
ray AS bisects ∠CAB
ray BT bisects ∠ABC
m∠APS = 180
m∠BPT = 180
PZ ⊥ ZA
PX ⊥ XA
PX ⊥ XB
PY ⊥ YB
PZ ⊥ ZC
PY ⊥ YC
Prove that:
ray CP bisects ∠BCA
The following properties may be helpful:
- if (ray BD bisects ∠ABC) and (m∠BPD = 180) and (PM ⊥ MB) and (PN ⊥ NB), then distance PM = distance PN
- if (ray BD bisects ∠ABC) and (m∠BPD = 180) and (PM ⊥ MB) and (PN ⊥ NB), then distance PM = distance PN
if the following are true:
- a = b
- a = c
then b = c
- if (distance PM = distance PN) and (PM ⊥ MB) and (PN ⊥ NB), then ray BP bisects ∠ABC
Please write your proof in the table below. Each row should contain one claim. The last claim is the statement that you are trying to prove.