Quiz (1 point)
Prove that:
△ABC ≅ △XYZ
The following properties may be helpful:
- if ∠ABC is a right angle, then m∠ABC = 90
- if ∠ABC is a right angle, then m∠ABC = 90
- if m∠ABC = 180, then ∠ABX and ∠XBC are supplementary
- if ∠ABC and ∠DEF are supplementary, then (m∠ABC) + (m∠DEF) = 180
if the following are true:
- a + b = c
- a = d
then d + b = c
if 90 + a = 180, then a = 90
- if m∠ABC = x, then m∠CBA = x
if the following are true:
- a = c
- b = c
then a = b
- if (distance AB = distance DE) and (m∠ABC = m∠DEF) and (distance BC = distance EF), then △ABC ≅ △DEF
if the following are true:
- a = c
- b = c
then a = b
- if △ABC ≅ △DEF, then distance AC = distance DF
if the following are true:
- a = b
- a = c
then b = c
- if distance XZ = distance YZ, then m∠ZXY = m∠ZYX
- if m∠ABC = 180, then m∠XAB = m∠XAC
- if m∠ABC = 180, then m∠XCB = m∠XCA
if the following are true:
- a = x
- b = y
- x = y
then a = b
- if (m∠ABC = m∠XYZ) and (m∠CAB = m∠ZXY) and (distance AC = distance XZ), then △BAC ≅ △YXZ
- if △ABC ≅ △DEF, then △BAC ≅ △EDF
- if (△ABC ≅ △GEF) and (△DEF ≅ △GEF), then △ABC ≅ △DEF
Please write your proof in the table below. Each row should contain one claim. The last claim is the statement that you are trying to prove.