Proof: Consecutive Interior Angles Theorem

Let's prove the following theorem:

if ∠WST and ∠YTS are supplementary, then WS || YT

W X Y Z S T

Proof:

View as a tree | View dependent proofs | Try proving it

Given
1 WST and ∠YTS are supplementary
Additional Assumptions
2 m∠WSX = 180
3 m∠YTZ = 180
Proof Table
# Claim Reason
1 (m∠WST) + (m∠YTS) = 180 if ∠WST and ∠YTS are supplementary, then (m∠WST) + (m∠YTS) = 180
2 m∠YTS = 180 + ((m∠WST) ⋅ (-1)) if (m∠WST) + (m∠YTS) = 180, then m∠YTS = 180 + ((m∠WST) ⋅ (-1))
3 WST and ∠TSX are supplementary if m∠WSX = 180, then ∠WST and ∠TSX are supplementary
4 (m∠WST) + (m∠TSX) = 180 if ∠WST and ∠TSX are supplementary, then (m∠WST) + (m∠TSX) = 180
5 m∠TSX = 180 + ((m∠WST) ⋅ (-1)) if (m∠WST) + (m∠TSX) = 180, then m∠TSX = 180 + ((m∠WST) ⋅ (-1))
6 m∠YTS = m∠TSX if m∠YTS = 180 + ((m∠WST) ⋅ (-1)) and m∠TSX = 180 + ((m∠WST) ⋅ (-1)), then m∠YTS = m∠TSX
7 WX || YZ if m∠WSX = 180 and m∠YTZ = 180 and m∠YTS = m∠TSX, then WX || YZ
8 WS || YT if WX || YZ and m∠WSX = 180 and m∠YTZ = 180, then WS || YT

Comments

Please log in to add comments