Proof: If Diagonals Congruent Then Rectangle
Let's prove the following theorem:
if WXYZ is a parallelogram and distance WY = distance XZ, then WXYZ is a rectangle
Proof:
Proof Table
# | Claim | Reason |
---|---|---|
1 | distance ZW = distance YX | if WXYZ is a parallelogram, then distance ZW = distance YX |
2 | distance WX = distance XW | distance WX = distance XW |
3 | distance XZ = distance WY | if distance WY = distance XZ, then distance XZ = distance WY |
4 | △WXZ ≅ △XWY | if distance WX = distance XW and distance XZ = distance WY and distance ZW = distance YX, then △WXZ ≅ △XWY |
5 | m∠ZWX = m∠YXW | if △WXZ ≅ △XWY, then m∠ZWX = m∠YXW |
6 | m∠ZWX = m∠WXY | if m∠ZWX = m∠YXW, then m∠ZWX = m∠WXY |
7 | WZ || XY | if WXYZ is a parallelogram, then WZ || XY |
8 | ZW || YX | if WZ || XY, then ZW || YX |
9 | ∠ZWX and ∠WXY are supplementary | if ZW || YX, then ∠ZWX and ∠WXY are supplementary |
10 | (m∠ZWX) + (m∠WXY) = 180 | if ∠ZWX and ∠WXY are supplementary, then (m∠ZWX) + (m∠WXY) = 180 |
11 | (m∠WXY) + (m∠WXY) = 180 | if (m∠ZWX) + (m∠WXY) = 180 and m∠ZWX = m∠WXY, then (m∠WXY) + (m∠WXY) = 180 |
12 | m∠WXY = 90 | if (m∠WXY) + (m∠WXY) = 180, then m∠WXY = 90 |
13 | ∠WXY is a right angle | if m∠WXY = 90, then ∠WXY is a right angle |
14 | WXYZ is a rectangle | if WXYZ is a parallelogram and ∠WXY is a right angle, then WXYZ is a rectangle |
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