Proof: If Diagonals Congruent Then Rectangle

Let's prove the following theorem:

if WXYZ is a parallelogram and distance WY = distance XZ, then WXYZ is a rectangle

Z W X Y

Proof:

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Given
1 WXYZ is a parallelogram
2 distance WY = distance XZ
Proof Table
# Claim Reason
1 distance ZW = distance YX if WXYZ is a parallelogram, then distance ZW = distance YX
2 distance WX = distance XW distance WX = distance XW
3 distance XZ = distance WY if distance WY = distance XZ, then distance XZ = distance WY
4 WXZ ≅ △XWY if distance WX = distance XW and distance XZ = distance WY and distance ZW = distance YX, then △WXZ ≅ △XWY
5 m∠ZWX = m∠YXW if △WXZ ≅ △XWY, then m∠ZWX = m∠YXW
6 m∠ZWX = m∠WXY if m∠ZWX = m∠YXW, then m∠ZWX = m∠WXY
7 WZ || XY if WXYZ is a parallelogram, then WZ || XY
8 ZW || YX if WZ || XY, then ZW || YX
9 ZWX and ∠WXY are supplementary if ZW || YX, then ∠ZWX and ∠WXY are supplementary
10 (m∠ZWX) + (m∠WXY) = 180 if ∠ZWX and ∠WXY are supplementary, then (m∠ZWX) + (m∠WXY) = 180
11 (m∠WXY) + (m∠WXY) = 180 if (m∠ZWX) + (m∠WXY) = 180 and m∠ZWX = m∠WXY, then (m∠WXY) + (m∠WXY) = 180
12 m∠WXY = 90 if (m∠WXY) + (m∠WXY) = 180, then m∠WXY = 90
13 WXY is a right angle if m∠WXY = 90, then ∠WXY is a right angle
14 WXYZ is a rectangle if WXYZ is a parallelogram and ∠WXY is a right angle, then WXYZ is a rectangle

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