Quiz (1 point)
Given that:
WXYZ is a rhombus
m∠WXY = 60
Prove that:
△YZW is an equilateral triangle
The following properties may be helpful:
- ((m∠YWX) + (m∠WXY)) + (m∠XYW) = 180
- if ABCD is a rhombus, then distance AB = distance BC
- if distance AB = distance CD, then distance AB = distance DC
- if distance XZ = distance YZ, then m∠ZXY = m∠ZYX
- if m∠ABC = m∠XYZ, then m∠CBA = m∠XYZ
if the following are true:
- a + b = c
- b = d
then a + d = c
if (a + b) + b = 180, then a + (b ⋅ 2) = 180
if the following are true:
- a + b = c
- a = d
then d + b = c
if 60 + (a ⋅ 2) = 180, then a = 60
if the following are true:
- a = c
- b = c
then a = b
if a = b, then b = a
- if (m∠ABC = m∠BCA) and (m∠BCA = m∠CAB), then △ABC is an equilateral triangle
- if WXYZ is a rhombus, then distance ZW = distance WX
- if WXYZ is a rhombus, then distance YZ = distance ZW
- if △ABC is an equilateral triangle, then distance CA = distance AB
if the following are true:
- a = c
- b = c
then a = b
- if distance AB = distance CD, then distance AB = distance DC
- if (distance AB = distance BC) and (distance BC = distance CA), then △ABC is an equilateral triangle
Please write your proof in the table below. Each row should contain one claim. The last claim is the statement that you are trying to prove.