Quiz (1 point)
Prove that:
△PXZ ∼ △XYZ
The following properties may be helpful:
- if m∠ABC = 180, then ∠ABX and ∠XBC are supplementary
- if ∠ABC and ∠DEF are supplementary, then (m∠ABC) + (m∠DEF) = 180
- if ∠ABC is a right angle, then m∠CBA = 90
if the following are true:
- a + b = c
- a = d
then d + b = c
if 90 + a = 180, then a = 90
- if m∠ABC = x, then m∠CBA = x
- if m∠ABC = 90, then ∠ABC is a right angle
- if (∠ABC is a right angle) and (∠DEF is a right angle), then m∠ABC = m∠DEF
- if m∠ABC = 180, then m∠ACX = m∠BCX
- if m∠ABC = m∠XYZ, then m∠ABC = m∠ZYX
- if (m∠CAB = m∠ZXY) and (m∠ABC = m∠XYZ), then △ABC ∼ △XYZ
- if △ABC ∼ △DEF, then △BCA ∼ △EFD
- if △ABC ∼ △DEF, then △DEF ∼ △ABC
Please write your proof in the table below. Each row should contain one claim. The last claim is the statement that you are trying to prove.