Proof: Log of an Exponential
Let's prove the following theorem:
logx(xp) = p
    
    
This theorem says that, if we take the log of an exponential, and the bases are the same, then the output is the exponent.
For example:
log2(23) = 3
We can confirm this by evaluating the logarithm on the left. We know that:
23 = 8
Using substitution:
log2(23) = log28
We also know that:
log28 = 3
Thus:
log2(23) = 3
Proof:
  
  
  Assumptions
    
    
      
  
| 1 | xp = z | 
|---|
| # | Claim | Reason | 
|---|---|---|
| 1 | logx(xp) = logxz | if xp = z, then logx(xp) = logxz | 
| 2 | logxz = p | if xp = z, then logxz = p | 
| 3 | logx(xp) = p | if logxz = p and logx(xp) = logxz, then logx(xp) = p | 
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