Proof: Log of an Exponential
Let's prove the following theorem:
logx(xp) = p
This theorem says that, if we take the log of an exponential, and the bases are the same, then the output is the exponent.
For example:
log2(23) = 3
We can confirm this by evaluating the logarithm on the left. We know that:
23 = 8
Using substitution:
log2(23) = log28
We also know that:
log28 = 3
Thus:
log2(23) = 3
Proof:
Assumptions
1 | xp = z |
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# | Claim | Reason |
---|---|---|
1 | logx(xp) = logxz | if xp = z, then logx(xp) = logxz |
2 | logxz = p | if xp = z, then logxz = p |
3 | logx(xp) = p | if logx(xp) = logxz and logxz = p, then logx(xp) = p |
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