Proof: When the Exponent is a Logarithm
Let's prove the following theorem:
b(logbx) = x
This theorem says that, if we have an exponential operation, and the exponent is a logarithm, and the bases are the same, then the output is the log input.
For example:
2(log28) = 8
We can confirm this by evaluating the logarithm on the left. We know that:
log28 = 3
Using substitution:
2(log28) = 23
We also know that:
23 = 8
Thus:
2(log28) = 8
Proof:
Assumptions
1 | bp = x |
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# | Claim | Reason |
---|---|---|
1 | logbx = p | if bp = x, then logbx = p |
2 | b(logbx) = bp | if logbx = p, then b(logbx) = bp |
3 | b(logbx) = x | if b(logbx) = bp and bp = x, then b(logbx) = x |
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