Proof: Inverse Example
Let's prove the following theorem:
((s ⋅ s) ⋅ (1 / 2)) ⋅ (1 / 2) = (s / 2) ⋅ (s / 2)
Proof:
# | Claim | Reason |
---|---|---|
1 | s ⋅ (1 / 2) = s / 2 | s ⋅ (1 / 2) = s / 2 |
2 | (s ⋅ (1 / 2)) ⋅ (s ⋅ (1 / 2)) = (s / 2) ⋅ (s / 2) | if s ⋅ (1 / 2) = s / 2 and s ⋅ (1 / 2) = s / 2, then (s ⋅ (1 / 2)) ⋅ (s ⋅ (1 / 2)) = (s / 2) ⋅ (s / 2) |
3 | (s ⋅ (1 / 2)) ⋅ (s ⋅ (1 / 2)) = ((s ⋅ s) ⋅ (1 / 2)) ⋅ (1 / 2) | (s ⋅ (1 / 2)) ⋅ (s ⋅ (1 / 2)) = ((s ⋅ s) ⋅ (1 / 2)) ⋅ (1 / 2) |
4 | ((s ⋅ s) ⋅ (1 / 2)) ⋅ (1 / 2) = (s / 2) ⋅ (s / 2) | if (s ⋅ (1 / 2)) ⋅ (s ⋅ (1 / 2)) = ((s ⋅ s) ⋅ (1 / 2)) ⋅ (1 / 2) and (s ⋅ (1 / 2)) ⋅ (s ⋅ (1 / 2)) = (s / 2) ⋅ (s / 2), then ((s ⋅ s) ⋅ (1 / 2)) ⋅ (1 / 2) = (s / 2) ⋅ (s / 2) |
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