Proof: Rearrange Sum 2
Let's prove the following theorem:
if (a + b) + c = d, then (b + a) + c = d
Proof:
Given
1 | (a + b) + c = d |
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# | Claim | Reason |
---|---|---|
1 | (a + b) + c = (b + a) + c | (a + b) + c = (b + a) + c |
2 | (b + a) + c = d | if (a + b) + c = (b + a) + c and (a + b) + c = d, then (b + a) + c = d |
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