Proof: Transitive 2

Let's prove the following theorem:

if the following are true:
  • x = ((b2) + (a2)) / 2
  • not (2 = 0)

then x = b + a

Proof:

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Given
1 x = ((b2) + (a2)) / 2
2 not (2 = 0)
Proof Table
# Claim Reason
1 ((b2) + (a2)) / 2 = b + a if not (2 = 0), then ((b2) + (a2)) / 2 = b + a
2 x = b + a if x = ((b2) + (a2)) / 2 and ((b2) + (a2)) / 2 = b + a, then x = b + a

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