Proof: Transitive 2
Let's prove the following theorem:
if the following are true:
- x = ((b ⋅ 2) + (a ⋅ 2)) / 2
- not (2 = 0)
then x = b + a
Proof:
Given
1 | x = ((b ⋅ 2) + (a ⋅ 2)) / 2 |
---|---|
2 | not (2 = 0) |
# | Claim | Reason |
---|---|---|
1 | ((b ⋅ 2) + (a ⋅ 2)) / 2 = b + a | if not (2 = 0), then ((b ⋅ 2) + (a ⋅ 2)) / 2 = b + a |
2 | x = b + a | if x = ((b ⋅ 2) + (a ⋅ 2)) / 2 and ((b ⋅ 2) + (a ⋅ 2)) / 2 = b + a, then x = b + a |
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