This theorem is equivalent to:
a2 - b2 = (a + b) ⋅ (a - b)
Here is a visualization of the theorem:
In this graph, the side of the largest square is a. The side of the orange square is b. Thus, the longer side of the blue rectangle is a - b.
The difference between the area of the largest square and the area of the orange square is:
a2 - b2
Visually, if we remove the orange square from the largest square, then we are left with 2 blue rectangles and the green square.
The area of 2 blue rectangles and the green square is:
2 ⋅ ((a - b) ⋅ b) + (a - b)2
If we factor out (a - b) from both terms, we get:
(2 ⋅ 1 ⋅ b + (a - b)) ⋅ (a - b)
(2 ⋅ 1 ⋅ b + (a - b)) is a + b. Therefore, the area of 2 blue rectangles and the green square is:
(a + b) ⋅ (a - b)
We can also prove this theorem using the distributive property, as shown below.
Quiz (1 point)
- a ⋅ (b + c) = (a ⋅ b) + (a ⋅ c)
- (a + b) ⋅ c = (a ⋅ c) + (b ⋅ c)
- (a + b) ⋅ (b ⋅ (-1)) = ((a ⋅ b) ⋅ (-1)) + ((b ⋅ b) ⋅ (-1))
- (b ⋅ a) + ((a ⋅ b) ⋅ (-1)) = 0
if the following are true:
- a = b
- c = d
then a + c = b + d
if b + c = 0, then (a + b) + (c + d) = a + d
if the following are true:
- a = b
- b = c
- c = d
then a = d
if a = b, then b = a
Please write your proof in the table below. Each row should contain one claim. The last claim is the statement that you are trying to prove.