Proof: Find Number Example 3

Let's prove the following theorem:

index of value 2 in [ 2, [ 1, [ ] ] ] = 0

Proof:

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Proof Table
# Claim Reason
1 index of value 2 in [ 2, [ 1, [ ] ] ] = index of value 2 in [ 2, [ 1, [ ] ] ] with current index 0 index of value 2 in [ 2, [ 1, [ ] ] ] = index of value 2 in [ 2, [ 1, [ ] ] ] with current index 0
2 2 = 2 2 = 2
3 index of value 2 in [ 2, [ 1, [ ] ] ] with current index 0 = 0 if 2 = 2, then index of value 2 in [ 2, [ 1, [ ] ] ] with current index 0 = 0
4 index of value 2 in [ 2, [ 1, [ ] ] ] = 0 if index of value 2 in [ 2, [ 1, [ ] ] ] = index of value 2 in [ 2, [ 1, [ ] ] ] with current index 0 and index of value 2 in [ 2, [ 1, [ ] ] ] with current index 0 = 0, then index of value 2 in [ 2, [ 1, [ ] ] ] = 0

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