Proof: Distributive Property Variation 4

Let's prove the following theorem:

(a ⋅ b) + (a ⋅ c) = a ⋅ (b + c)

Proof:

View as a tree | View dependent proofs | Try proving it

Proof Table
# Claim Reason
1 a ⋅ (b + c) = (a ⋅ b) + (a ⋅ c) a ⋅ (b + c) = (a ⋅ b) + (a ⋅ c)
2 (a ⋅ b) + (a ⋅ c) = a ⋅ (b + c) if a ⋅ (b + c) = (a ⋅ b) + (a ⋅ c), then (a ⋅ b) + (a ⋅ c) = a ⋅ (b + c)

Comments

Please log in to add comments