Proof: Minimum Example

Let's prove the following theorem:

minimum value of stack [ [ 0, [ ] ], [ [ 1, [ ] ], [ ] ] ] = [ 0, [ ] ]

Proof:

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Proof Table
# Claim Reason
1 [ 0, [ ] ] is less than [ 1, [ ] ] [ 0, [ ] ] is less than [ 1, [ ] ]
2 minimum value of stack [ [ 1, [ ] ], [ ] ] = [ 1, [ ] ] minimum value of stack [ [ 1, [ ] ], [ ] ] = [ 1, [ ] ]
3 [ 1, [ ] ] = minimum value of stack [ [ 1, [ ] ], [ ] ] if minimum value of stack [ [ 1, [ ] ], [ ] ] = [ 1, [ ] ], then [ 1, [ ] ] = minimum value of stack [ [ 1, [ ] ], [ ] ]
4 [ 0, [ ] ] is less than [ 1, [ ] ] = [ 0, [ ] ] is less than (minimum value of stack [ [ 1, [ ] ], [ ] ]) if [ 1, [ ] ] = minimum value of stack [ [ 1, [ ] ], [ ] ], then [ 0, [ ] ] is less than [ 1, [ ] ] = [ 0, [ ] ] is less than (minimum value of stack [ [ 1, [ ] ], [ ] ])
5 [ 0, [ ] ] is less than (minimum value of stack [ [ 1, [ ] ], [ ] ]) if [ 0, [ ] ] is less than [ 1, [ ] ] and [ 0, [ ] ] is less than [ 1, [ ] ] = [ 0, [ ] ] is less than (minimum value of stack [ [ 1, [ ] ], [ ] ]), then [ 0, [ ] ] is less than (minimum value of stack [ [ 1, [ ] ], [ ] ])
6 minimum value of stack [ [ 0, [ ] ], [ [ 1, [ ] ], [ ] ] ] = [ 0, [ ] ] if [ 0, [ ] ] is less than (minimum value of stack [ [ 1, [ ] ], [ ] ]), then minimum value of stack [ [ 0, [ ] ], [ [ 1, [ ] ], [ ] ] ] = [ 0, [ ] ]

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