Quiz (1 point)
Prove that:
remaining elements after [ [ 0, [  ] ], [ [ 1, [  ] ], [  ] ] ] is popped at index [ 1, [  ] ] = [ [ 0, [  ] ], [  ] ]
The following properties may be helpful:
    - remaining elements after xs is popped at index index = reverse of (remaining elements after xs is popped at index index and visited stack is [ ])
- remaining elements after [ [ 0, [ ] ], [ [ 1, [ ] ], [ ] ] ] is popped at index [ 1, [ ] ] and visited stack is [ ] = [ [ 0, [ ] ], [ ] ]
- reverse of [ [ 0, [ ] ], [ ] ] = [ [ 0, [ ] ], [ ] ]
- if remaining elements after [ [ 0, [ ] ], [ [ 1, [ ] ], [ ] ] ] is popped at index [ 1, [ ] ] and visited stack is [ ] = [ [ 0, [ ] ], [ ] ], then reverse of (remaining elements after [ [ 0, [ ] ], [ [ 1, [ ] ], [ ] ] ] is popped at index [ 1, [ ] ] and visited stack is [ ]) = reverse of [ [ 0, [ ] ], [ ] ] 
- if the following are true: - a = b
- b = c
 - then a = c 
- if the following are true: - a = b
- b = c
 - then a = c 
Please write your proof in the table below. Each row should contain one claim. The last claim is the statement that you are trying to prove.