Proof: Substitution 4
Let's prove the following theorem:
if a = b, then (a ⋅ c) + d = (b ⋅ c) + d
    
    
    
    Proof:
  
      
      Given
      
    
    
      
  
  
| 1 | a = b | 
|---|
| # | Claim | Reason | 
|---|---|---|
| 1 | a ⋅ c = b ⋅ c | if a = b, then a ⋅ c = b ⋅ c | 
| 2 | (a ⋅ c) + d = (b ⋅ c) + d | if a ⋅ c = b ⋅ c, then (a ⋅ c) + d = (b ⋅ c) + d | 
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