Proof: Rearrange Sum
Let's prove the following theorem:
if (a + b) + c = d, then (a + c) + b = d
Proof:
Given
1 | (a + b) + c = d |
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# | Claim | Reason |
---|---|---|
1 | (a + b) + c = (a + c) + b | (a + b) + c = (a + c) + b |
2 | (a + c) + b = d | if (a + b) + c = (a + c) + b and (a + b) + c = d, then (a + c) + b = d |
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