Proof: Rearrange Sum 2
Let's prove the following theorem:
if (a + b) + c = d, then (b + a) + c = d
    
    
    
    Proof:
  
      
      Given
      
    
    
      
  
  
| 1 | (a + b) + c = d | 
|---|
| # | Claim | Reason | 
|---|---|---|
| 1 | (a + b) + c = (b + a) + c | (a + b) + c = (b + a) + c | 
| 2 | (b + a) + c = d | if (a + b) + c = (b + a) + c and (a + b) + c = d, then (b + a) + c = d | 
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