Proof: Reordering Terms Theorem
Let's prove the following theorem:
(a ⋅ b) ⋅ c = (c ⋅ a) ⋅ b
Proof:
| # | Claim | Reason |
|---|---|---|
| 1 | (a ⋅ b) ⋅ c = (a ⋅ c) ⋅ b | (a ⋅ b) ⋅ c = (a ⋅ c) ⋅ b |
| 2 | a ⋅ c = c ⋅ a | a ⋅ c = c ⋅ a |
| 3 | (a ⋅ c) ⋅ b = (c ⋅ a) ⋅ b | if a ⋅ c = c ⋅ a, then (a ⋅ c) ⋅ b = (c ⋅ a) ⋅ b |
| 4 | (a ⋅ b) ⋅ c = (c ⋅ a) ⋅ b | if (a ⋅ b) ⋅ c = (a ⋅ c) ⋅ b and (a ⋅ c) ⋅ b = (c ⋅ a) ⋅ b, then (a ⋅ b) ⋅ c = (c ⋅ a) ⋅ b |
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