Proof: Write Call Function Build Tab At 11

Let's prove the following theorem:

if the following are true:

expression state at time 11 = "call_build_args"
Parameters List at time 11 = [ x, [ ] ]
the tab at time 11 = 0

then the tab at time 12 = 0

Proof:

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Given

1	expression state at time 11 = "call_build_args"
2	Parameters List at time 11 = [ x, [ ] ]
3	the tab at time 11 = 0

Proof Table

#	Claim	Reason
1	the tab at time (11 + 1) = the tab at time 11	if expression state at time 11 = "call_build_args" and Parameters List at time 11 = [ x, [ ] ], then the tab at time (11 + 1) = the tab at time 11 (Call Build Args Unchanged on Params (2))
2	the tab at time (11 + 1) = 0	if the tab at time (11 + 1) = the tab at time 11 and the tab at time 11 = 0, then the tab at time (11 + 1) = 0 (Transitive Property of Equality)
3	11 + 1 = 12	11 + 1 = 12 (Fixed Value Statement)
4	the tab at time (11 + 1) = the tab at time 12	if 11 + 1 = 12, then the tab at time (11 + 1) = the tab at time 12 (Substitution)
5	the tab at time 12 = 0	if the tab at time (11 + 1) = the tab at time 12 and the tab at time (11 + 1) = 0, then the tab at time 12 = 0 (Transitive Property of Equality Variation 2)

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