Proof: Write Stmt Tab At Unchanged Expr26

Let's prove the following theorem:

if the following are true:

the line at time 26 = 5
the tab at time 26 = 0
statement at line 5, tab 0 = b = add_three(a)
expression state at time 26 = "end_expr"

then the tab at time 27 = 0

Proof:

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Given

1	the line at time 26 = 5
2	the tab at time 26 = 0
3	statement at line 5, tab 0 = `b = add_three(a)`
4	expression state at time 26 = "end_expr"

Proof Table

#	Claim	Reason
1	the tab at time (26 + 1) = the tab at time 26	if the line at time 26 = 5 and the tab at time 26 = 0 and statement at line 5, tab 0 = `b = add_three(a)` and expression state at time 26 = "end_expr", then the tab at time (26 + 1) = the tab at time 26 (Assign Variable to Call Result (3))
2	the tab at time (26 + 1) = 0	if the tab at time (26 + 1) = the tab at time 26 and the tab at time 26 = 0, then the tab at time (26 + 1) = 0 (Transitive Property of Equality)
3	26 + 1 = 27	26 + 1 = 27 (Fixed Value Statement)
4	the tab at time (26 + 1) = the tab at time 27	if 26 + 1 = 27, then the tab at time (26 + 1) = the tab at time 27 (Substitution)
5	the tab at time 27 = 0	if the tab at time (26 + 1) = the tab at time 27 and the tab at time (26 + 1) = 0, then the tab at time 27 = 0 (Transitive Property of Equality Variation 2)

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