Proof: Write Stmt Control Map At Unchanged Expr0

Let's prove the following theorem:

if the following are true:
  • the line at time 0 = 1
  • the tab at time 0 = 0
  • statement at line 1, tab 0 = if __eq__(3, 3):
  • expression state at time 0 = "not_expr"
  • Control Map at time 0 = [ ]

then Control Map at time 1 = [ ]

Proof:

View as a tree | View dependent proofs | Try proving it

Given
1 the line at time 0 = 1
2 the tab at time 0 = 0
3 statement at line 1, tab 0 = if __eq__(3, 3):
4 expression state at time 0 = "not_expr"
5 Control Map at time 0 = [ ]
Proof Table
# Claim Reason
1 Control Map at time (0 + 1) = Control Map at time 0 if the line at time 0 = 1 and the tab at time 0 = 0 and statement at line 1, tab 0 = if __eq__(3, 3): and expression state at time 0 = "not_expr", then Control Map at time (0 + 1) = Control Map at time 0
2 Control Map at time (0 + 1) = [ ] if Control Map at time (0 + 1) = Control Map at time 0 and Control Map at time 0 = [ ], then Control Map at time (0 + 1) = [ ]
3 0 + 1 = 1 0 + 1 = 1
4 Control Map at time (0 + 1) = Control Map at time 1 if 0 + 1 = 1, then Control Map at time (0 + 1) = Control Map at time 1
5 Control Map at time 1 = [ ] if Control Map at time (0 + 1) = Control Map at time 1 and Control Map at time (0 + 1) = [ ], then Control Map at time 1 = [ ]

Comments

Please log in to add comments