Proof: Write Stmt Expr State At Unchanged 13
Let's prove the following theorem:
if the following are true:
- the line at time 13 = 3
- the tab at time 13 = 0
- statement at line 3, tab 0 =
else:
- expression state at time 13 = "not_expr"
then expression state at time 14 = "not_expr"
Proof:
Given
1 | the line at time 13 = 3 |
---|---|
2 | the tab at time 13 = 0 |
3 | statement at line 3, tab 0 = else: |
4 | expression state at time 13 = "not_expr" |
# | Claim | Reason |
---|---|---|
1 | expression state at time (13 + 1) = expression state at time 13 | if the line at time 13 = 3 and the tab at time 13 = 0 and statement at line 3, tab 0 = else: , then expression state at time (13 + 1) = expression state at time 13 |
2 | expression state at time (13 + 1) = "not_expr" | if expression state at time (13 + 1) = expression state at time 13 and expression state at time 13 = "not_expr", then expression state at time (13 + 1) = "not_expr" |
3 | 13 + 1 = 14 | 13 + 1 = 14 |
4 | expression state at time (13 + 1) = expression state at time 14 | if 13 + 1 = 14, then expression state at time (13 + 1) = expression state at time 14 |
5 | expression state at time 14 = "not_expr" | if expression state at time (13 + 1) = expression state at time 14 and expression state at time (13 + 1) = "not_expr", then expression state at time 14 = "not_expr" |
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