Proof: Do Arg Stack At Unchanged 16
Let's prove the following theorem:
if the following are true:
- expression state at time 16 = "return"
- arguments stack at time 16 = [ [ 1, [ ] ], [ ] ]
then arguments stack at time 17 = [ [ 1, [ ] ], [ ] ]
Proof:
Given
1 | expression state at time 16 = "return" |
---|---|
2 | arguments stack at time 16 = [ [ 1, [ ] ], [ ] ] |
# | Claim | Reason |
---|---|---|
1 | arguments stack at time (16 + 1) = arguments stack at time 16 | if expression state at time 16 = "return", then arguments stack at time (16 + 1) = arguments stack at time 16 |
2 | arguments stack at time (16 + 1) = [ [ 1, [ ] ], [ ] ] | if arguments stack at time (16 + 1) = arguments stack at time 16 and arguments stack at time 16 = [ [ 1, [ ] ], [ ] ], then arguments stack at time (16 + 1) = [ [ 1, [ ] ], [ ] ] |
3 | 16 + 1 = 17 | 16 + 1 = 17 |
4 | arguments stack at time (16 + 1) = arguments stack at time 17 | if 16 + 1 = 17, then arguments stack at time (16 + 1) = arguments stack at time 17 |
5 | arguments stack at time 17 = [ [ 1, [ ] ], [ ] ] | if arguments stack at time (16 + 1) = arguments stack at time 17 and arguments stack at time (16 + 1) = [ [ 1, [ ] ], [ ] ], then arguments stack at time 17 = [ [ 1, [ ] ], [ ] ] |
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