Proof: Do Arg Stack At Unchanged 21

Let's prove the following theorem:

if the following are true:

expression state at time 21 = "call_function_begin"
arguments stack at time 21 = [ ]

then arguments stack at time 22 = [ ]

Proof:

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Given

1	expression state at time 21 = "call_function_begin"
2	arguments stack at time 21 = [ ]

Proof Table

#	Claim	Reason
1	arguments stack at time (21 + 1) = arguments stack at time 21	if expression state at time 21 = "call_function_begin", then arguments stack at time (21 + 1) = arguments stack at time 21 (Assign Parent (2))
2	arguments stack at time (21 + 1) = [ ]	if arguments stack at time (21 + 1) = arguments stack at time 21 and arguments stack at time 21 = [ ], then arguments stack at time (21 + 1) = [ ] (Transitive Property of Equality)
3	21 + 1 = 22	21 + 1 = 22 (Fixed Value Statement)
4	arguments stack at time (21 + 1) = arguments stack at time 22	if 21 + 1 = 22, then arguments stack at time (21 + 1) = arguments stack at time 22 (Substitution)
5	arguments stack at time 22 = [ ]	if arguments stack at time (21 + 1) = arguments stack at time 22 and arguments stack at time (21 + 1) = [ ], then arguments stack at time 22 = [ ] (Transitive Property of Equality Variation 2)

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