Proof: Write Stmt Class Defs At Unchanged 1
Let's prove the following theorem:
if the following are true:
- the line at time 1 = 2
- the tab at time 1 = 0
- statement at line 2, tab 0 =
while __lt__(a, 2):
- Class Map at time 1 = [ ]
then Class Map at time 2 = [ ]
Proof:
Given
1 | the line at time 1 = 2 |
---|---|
2 | the tab at time 1 = 0 |
3 | statement at line 2, tab 0 = while __lt__(a, 2): |
4 | Class Map at time 1 = [ ] |
# | Claim | Reason |
---|---|---|
1 | Class Map at time (1 + 1) = Class Map at time 1 | if the line at time 1 = 2 and the tab at time 1 = 0 and statement at line 2, tab 0 = while __lt__(a, 2): , then Class Map at time (1 + 1) = Class Map at time 1 |
2 | Class Map at time (1 + 1) = [ ] | if Class Map at time (1 + 1) = Class Map at time 1 and Class Map at time 1 = [ ], then Class Map at time (1 + 1) = [ ] |
3 | 1 + 1 = 2 | 1 + 1 = 2 |
4 | Class Map at time (1 + 1) = Class Map at time 2 | if 1 + 1 = 2, then Class Map at time (1 + 1) = Class Map at time 2 |
5 | Class Map at time 2 = [ ] | if Class Map at time (1 + 1) = Class Map at time 2 and Class Map at time (1 + 1) = [ ], then Class Map at time 2 = [ ] |
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