Proof: Write Stmt Class Defs At Unchanged 35
Let's prove the following theorem:
if the following are true:
- the line at time 35 = 3
- the tab at time 35 = 1
- statement at line 3, tab 1 =
a = __add__(a, 1)
- Class Map at time 35 = [ ]
then Class Map at time 36 = [ ]
Proof:
Given
1 | the line at time 35 = 3 |
---|---|
2 | the tab at time 35 = 1 |
3 | statement at line 3, tab 1 = a = __add__(a, 1) |
4 | Class Map at time 35 = [ ] |
# | Claim | Reason |
---|---|---|
1 | Class Map at time (35 + 1) = Class Map at time 35 | if the line at time 35 = 3 and the tab at time 35 = 1 and statement at line 3, tab 1 = a = __add__(a, 1) , then Class Map at time (35 + 1) = Class Map at time 35 |
2 | Class Map at time (35 + 1) = [ ] | if Class Map at time (35 + 1) = Class Map at time 35 and Class Map at time 35 = [ ], then Class Map at time (35 + 1) = [ ] |
3 | 35 + 1 = 36 | 35 + 1 = 36 |
4 | Class Map at time (35 + 1) = Class Map at time 36 | if 35 + 1 = 36, then Class Map at time (35 + 1) = Class Map at time 36 |
5 | Class Map at time 36 = [ ] | if Class Map at time (35 + 1) = Class Map at time 36 and Class Map at time (35 + 1) = [ ], then Class Map at time 36 = [ ] |
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