Proof: Get Begin Expr Params Unchanged6
Let's prove the following theorem:
if the following are true:
- the expression at time 6 = 3
- expression state at time 6 = "begin_expr"
- 3 is constant
- arguments stack at time 6 = [ [ ], [ ] ]
then arguments stack at time 7 = [ [ ], [ ] ]
Proof:
Given
1 | the expression at time 6 = 3 |
---|---|
2 | expression state at time 6 = "begin_expr" |
3 | 3 is constant |
4 | arguments stack at time 6 = [ [ ], [ ] ] |
# | Claim | Reason |
---|---|---|
1 | arguments stack at time (6 + 1) = arguments stack at time 6 | if expression state at time 6 = "begin_expr" and the expression at time 6 = 3 and 3 is constant, then arguments stack at time (6 + 1) = arguments stack at time 6 |
2 | arguments stack at time (6 + 1) = [ [ ], [ ] ] | if arguments stack at time (6 + 1) = arguments stack at time 6 and arguments stack at time 6 = [ [ ], [ ] ], then arguments stack at time (6 + 1) = [ [ ], [ ] ] |
3 | 6 + 1 = 7 | 6 + 1 = 7 |
4 | arguments stack at time (6 + 1) = arguments stack at time 7 | if 6 + 1 = 7, then arguments stack at time (6 + 1) = arguments stack at time 7 |
5 | arguments stack at time 7 = [ [ ], [ ] ] | if arguments stack at time (6 + 1) = arguments stack at time 7 and arguments stack at time (6 + 1) = [ [ ], [ ] ], then arguments stack at time 7 = [ [ ], [ ] ] |
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