Proof: Get Iterate Parent 5

Let's prove the following theorem:

if the following are true:

expression state at time 5 = "iterate_args"
arguments stack at time 5 = [ [ 3, [ ] ], [ ] ]
parent stack at time 5 = [ __eq__(1, 3), [ ] ]

then parent stack at time 6 = [ __eq__(1, 3), [ ] ]

Proof:

View as a tree | View dependent proofs | Try proving it

Given

1	expression state at time 5 = "iterate_args"
2	arguments stack at time 5 = [ [ 3, [ ] ], [ ] ]
3	parent stack at time 5 = [ `__eq__(1, 3)`, [ ] ]

Proof Table

#	Claim	Reason
1	parent stack at time (5 + 1) = parent stack at time 5	if expression state at time 5 = "iterate_args" and arguments stack at time 5 = [ [ 3, [ ] ], [ ] ], then parent stack at time (5 + 1) = parent stack at time 5 (Do Iterage Args (4))
2	parent stack at time (5 + 1) = [ `__eq__(1, 3)`, [ ] ]	if parent stack at time (5 + 1) = parent stack at time 5 and parent stack at time 5 = [ `__eq__(1, 3)`, [ ] ], then parent stack at time (5 + 1) = [ `__eq__(1, 3)`, [ ] ] (Transitive Property of Equality)
3	5 + 1 = 6	5 + 1 = 6 (Fixed Value Statement)
4	parent stack at time (5 + 1) = parent stack at time 6	if 5 + 1 = 6, then parent stack at time (5 + 1) = parent stack at time 6 (Substitution)
5	parent stack at time 6 = [ `__eq__(1, 3)`, [ ] ]	if parent stack at time (5 + 1) = parent stack at time 6 and parent stack at time (5 + 1) = [ `__eq__(1, 3)`, [ ] ], then parent stack at time 6 = [ `__eq__(1, 3)`, [ ] ] (Transitive Property of Equality Variation 2)

Comments

Please log in to add comments